研究文章

维支流细分搭配方法的问题

表3

对比的绝对误差(2)为例

由(25] 通过细分收集算法

0.0 0.000000000000000000 0.00000000000000
0.1 2.685102500000001e−3 1.08473333363529e−5
0.2 2.021935000000003e−3 3.28980192095263e−5
0.3 1.523418999999915e−4 4.87156744417711e−5
0.4 2.201747400000009e−3 5.84689338488098e−5
0.5 3.015473299999988e−3 6.18727572535005e−5
0.6 2.201747400000009e−3 5.84689338488931e−5
0.7 1.523418999999915e−4 4.87156744419098e−5
0.8 2.021935000000003e−3 3.28980192097483e−5
0.9 2.685102500000001e−3 1.08473333366513e−5
1.0 0.000000000000000000 0.00000000000085e−5